ME 203 Homework

You are viewing a reply to Fall 2008  

Homework 04

United States
Hummmm, whatever could it be...
Problem 2...the solutions manual says that x = acostheta + sqrt(b2-a2sin2theta). How did they get that second term?
They got that x equation from using trig. For the first part of x, they're looking at the triangle w/ sides A, B, and the bottom side is a small part of x, or "d". So "d" is acostheta. For the second part of x, they're looking at the other triagle w/ sides B, P, and the other side of x, or "e," we'll call it. By trig, "e" is equal to the sqrt(b2-a2sin2theta). Hope that helps! For clarification: x = d + e
Oh wow, I can't believe I forgot about the pythagorean theorem. Makes perfect sense now. Thanks Liliya!

Newest Blog Posts

  1. Huygens clocks and synchronization
    Tue 26 of Aug, 2014 06:57 EDT
  2. MATLAB animation
    Tue 01 of Oct, 2013 17:27 EDT
  3. Structural Vibrations
    Wed 01 of May, 2013 09:52 EDT